"An alternative spiral matrix traversal using list.size() for dynamic termination, eliminating boundary variables:Innovative"
class Solution { public List spiralOrder(int[][] matrix) { if (matrix == null || matrix.length == 0) return new ArrayList(); int m=matrix.length; int n=matrix[0].length; int totalelements=m*n; List list = new ArrayList(); for(int layer=0;layer

class Solution {
public List spiralOrder(int[][] matrix) {
if (matrix == null || matrix.length == 0) return new ArrayList<>();
int m=matrix.length;
int n=matrix[0].length;
int totalelements=m*n;
List list = new ArrayList<>();
for(int layer=0;layer =layer ;j--){
list.add(matrix[row][j]);
}
col=layer;
for(int i=m-2-layer; list.size()=layer+1 ;i--){
list.add(matrix[i][col]);
}
}
return list;
}
}